I suppose it's possible the protective coating has a higher ignite point... but I'm not sure how I see that really helps unless it also provides an insulation type effect.

Let's say the ignite point for an object is 100 degrees celsius and the object burns at 180 degrees celsius. And you put it in a safe, the safe having an ignite point of 200 degrees celsius. Just to ensure the concept I'm trying to get at, I'll add that the safe is not equipped with any kind of insulation... in other words, the internal temperature matches the external temperature.

You place the safe in fire at 150 degrees celsius for a while. Then pull it out. Wouldn't the object inside have burned while the safe itself has not burned?

I'm not concerned with burning food... I'm more concerned with knowing when my frying pan is going to burst into flames on me :)

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